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Let f(x)=x2−6xsgn(x2−4)+5, where sgn(y) denotes the signum function of y. Then the number of solution(s) of f(x)=0 is |
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Answer» Let f(x)=x2−6xsgn(x2−4)+5, where sgn(y) denotes the signum function of y. Then the number of solution(s) of f(x)=0 is |
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