Let f(x)=(x3+(a−1)x2+(b−a)x−b)|x2+8x+6|, where a,b∈R. If f(x) – InterviewSolution

1.	Let f(x)=(x3+(a−1)x2+(b−a)x−b)\|x2+8x+6\|, where a,b∈R. If f(x) is derivable in (−∞,∞), then the value of (a+b4) is
Answer» Let $f (x) = (x^{3} + (a - 1) x^{2} + (b - a) x - b) \| x^{2} + 8 x + 6 \|,$ where $a, b \in R$ . If $f (x)$ is derivable in $(- \infty, \infty)$ , then the value of $(\frac{a + b}{4})$ is

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