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Let f : X → Y be a given function, then f −1 exists (as f is invertible) if : (a) f is onto (b) f is one-one but not onto (c) f is one-one and onto (d) f is one-one |
Answer» <p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Correct option to (c) f is one-one and onto </strong></span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">f is invertible or f ′ exists, if f is one-one onto.</span></span></p> | |