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Let f : X → Y be a given function, then f −1 exists (as f is invertible) if : (a) f is onto (b) f is one-one but not onto (c) f is one-one and onto (d) f is one-one |
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Answer» Correct option to (c) f is one-one and onto Explanation: f is invertible or f ′ exists, if f is one-one onto. |
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