1.

Let G be the centroid of triangle ABC and the circumcircle of triangle AGC touches the side AB at A If AC = 1, then the length of the median of triangle ABC through the vertex A is equal to

Answer»

`(SQRT3)/(2)`
`(1)/(2)`
`(2)/(sqrt3)`
`(5)/(sqrt2)`

SOLUTION :We have `AD = sqrt((2B^(2) + 2c^(2) -a^(2))/(4)) = (sqrt3b)/(2)`
If `b = 1 " then " AD = (sqrt3)/(2)`


Discussion

No Comment Found

Related InterviewSolutions