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Let G be the centroid of triangle ABC and the circumcircle of triangle AGC touches the side AB at A If BC = 6, AC = 8, then the length of side AB is equal to |
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Answer» `(1)/(2)` `FG xx FC = FA^(2)` `RARR (1)/(3) (FC^(2)) = FA^(2)` `rArr (2a^(2) + 2b^(2) -C^(2))/(3 xx4) = (c^(2))/(4)` (Using Apollonious theorem) `rArr 2C^(2) = a^(2) + b^(2)` |
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