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Let g(x)=e^f(x)), g(x+1)=xg(x), then (g'((2n+1)/(2))g((1)/(2))-g'((1)/(2))g((2n+1)/(2)))/(g((2n+1)/(2))g((1)/(2))), where n in N, is |
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Answer» `2 (1+(1)/(2)+(1)/(3)+….+(1)/(n))` |
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