InterviewSolution
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InterviewSolution
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Let `[in_(0)]` denote the dimensional formula of the permittivity of vacuum. If `M = mass, L = length, T = time and A = elctric current`, then :A. ` [varepsilon_0] = M ^(-1) L^2 A^(-2)]`B. ` [varepsilon_0] = M ^(-1) L^2 A^(-2)]`C. ` [varepsilon_0] = M ^(-1) L^3 A^(-2)]`D. ` [varepsilon_0] = M ^(-1) L^3 A^(-2)]` |
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Answer» Correct Answer - D `(Energy)/(Volume 0 1/2 in_0 = 1/2 in_0 [F/q]^2` ` (ML^2 T^(-2))/L^2 = in_0 [(MLT^(-2)/(AT)]^2` `in_0 rarr M^(-1) L^(-3) T^4 A^2 1`. |
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