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Let `[in_(0)]` denote the dimensional formula of the permittivity of vacuum. If M= mass, L=length, T=Time and A= electric current, then:A. `[in_(0]=[M^(-1)L^(-3)T^(2)A]`B. `[in_(0)]=[M^(-1)L^(-3)T^(4)A^(2)]`C. `[in_(0)]=[M^(-1)L^(2)T^(-1)A^(-2)]`D. `[in_(0)]=[M^(-1)L^(2)T^(-1)A]` |
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Answer» Correct Answer - B `F=(1)/(4pi in_(0))(q_(1)q_(2))/r^(2)rArr [MLT^(-2)]=[1/in_(0)] (A^(2)T^(2))/L^(2)` `rArr [epsilon_(0)]=[M^(-1)L^(-3)T^(4)A^(2)]` |
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