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Let `[in_(0)]` denote the dimensional formula of the permittivity of vacuum. If M= mass, L=length, T=Time and A= electric current, then:A. `[epsilon_(0)]=[M^(-1)L^(-3)T^(4)A^(2)]`B. `[epsilon_(0)]=[M^(-1)L^(2)T^(-1)A^(-2)]`C. `[epsilon_(0)]=[M^(-1)L^(2)T^(-1)A]`D. `[epsilon_(0)]=[M^(-1)L^(-3)T^(2)A]` |
Answer» Correct Answer - A | |