Let In=1∫0xnx2012−1 dx, Jn=1∫0xnx2013+1 dx for all n>2012, n∈N and matrix A=(aij)3×3, where aij={I2012+i−Ii, i=j 0, i≠j and matrix B=(bij)3×3, where bij={J2016+j+Jj+3, i=j 0, i≠j. Then the value of trace(A−1)+|B−1| is

Let In=1∫0xnx2012−1 dx, Jn=1∫0xnx2013+1 dx for all n>2012, n∈N

1.	Let In=1∫0xnx2012−1 dx, Jn=1∫0xnx2013+1 dx for all n>2012, n∈N and matrix A=(aij)3×3, where aij={I2012+i−Ii, i=j 0, i≠j and matrix B=(bij)3×3, where bij={J2016+j+Jj+3, i=j 0, i≠j. Then the value of trace(A−1)+\|B−1\| is
Answer» Let $I_{n} = 1 \int 0 \frac{x^{n}}{x^{2012} - 1} d x, J_{n} = 1 \int 0 \frac{x^{n}}{x^{2013} + 1} d x$ for all $n > 2012, n \in N$ and matrix $A = (a_{i j})_{3 \times 3},$ where $a_{i j} = {\begin{matrix} I_{2012 + i} - I_{i}, i = j 0, i \neq j \end{matrix}$ and matrix $B = (b_{i j})_{3 \times 3},$ where $b_{i j} = {\begin{matrix} J_{2016 + j} + J_{j + 3}, i = j 0, i \neq j \end{matrix} .$ Then the value of $trace (A^{- 1}) + \| B^{- 1} \|$ is