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Let `L_(1)` be the line `vecr_(1)=2hati+hatj-hatk+lamda(hati+2hatk)` and let `L_(2)` be the line `vecr_(2)=3hati+hatj-hatk+mu(hati+hatj+hatk)`. Let `pi` be the plane which contains the line `L_(1)` and is parallel to `L_(2)`. The distance of the plane `pi` from the origin isA. `sqrt(2//7)`B. `1//7`C. `sqrt6`D. none |
Answer» Correct Answer - a Equation of the plane containing `L_(1),A(x-2)+B(y-1)+C(z+1)=0` where `A+2C=0,A+B-C=0` `impliesA=-2C-,B=3C,C=C` `implies"Plane is"-2(x-2)+3(y-1)+z+1=0` or `2x-3y-z-2=0` Hence, `p=|(-2)/(sqrt14)|=sqrt((2)/(7))` |
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