Let `lim_(n->oo)sum_(k=1)^n(lambdak^4+2k^3+k^2+k+1)/(3n^5+n^2+n+5k)=1/3` then `lambda` is equal to

Let `lim_(n->oo)sum_(k=1)^n(lambdak^4+2k^3+k^2+k+1)/(3n^5+n^2+n+5k)=1/

1.	Let `lim_(n->oo)sum_(k=1)^n(lambdak^4+2k^3+k^2+k+1)/(3n^5+n^2+n+5k)=1/3` then `lambda` is equal to
Answer» Correct Answer - 5 `lim_(nto oo) sum_(k=1)^(n) (((lamdak^(4)+2k^(3)+k^(2)+k+1))/(n^(5)))/(((3n^(5)+n^(2)+n+5k))/(n^(5)))=int_(0)^(1)(lamdax^(4)dx)/3=(lamda)/3((x^(5))/5)_(0)^(1)=(lamda)/15`

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Let `lim_(n->oo)sum_(k=1)^n(lambdak^4+2k^3+k^2+k+1)/(3n^5+n^2+n+5k)=1/3` then `lambda` is equal to

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