1.

let \log_a1 = y ->1 = a^y (by Defenation) ->then how can a^y = a^{0 } which is -> y = 0

Answer» let \log_a1 = y ->1 = a^y (by Defenation) ->then how can a^y = a^{0 } which is -> y = 0


Discussion

No Comment Found