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| 1. |
let \log_a1 = y ->1 = a^y (by Defenation) ->then how can a^y = a^{0 } which is -> y = 0 |
| Answer» let \log_a1 = y ->1 = a^y (by Defenation) ->then how can a^y = a^{0 } which is -> y = 0 | |