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Let `M=10^[10^[10^10]`.If M ends with N zeroes and N ends with P zeroes.The number of digits in P are: |
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Answer» `M =10^(10^(10^10))` We know, `10^a` will always have `a` zeroes. `:. N = (10^(10^10))` Similarly,`P = 10^10=10000000000` So, `P` has `11` digits. |
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