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Let M={A=(abcd):a,b,c,d∈{±3,±2,±1,0}}. Define f:M→Z, as f(A)=det(A), for all A∈M, where Z is set of all integers. Then the number of A∈M such that f(A)=15 is equal to

Answer» Let M={A=(abcd):a,b,c,d{±3,±2,±1,0}}. Define f:MZ, as f(A)=det(A), for all AM, where Z is set of all integers. Then the number of AM such that f(A)=15 is equal to


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