Let m,n∈N and gcd(2,n)=1. If 30(300)+29(301)+⋯+2(3028)+1(3029)=n� – InterviewSolution

1.	Let m,n∈N and gcd(2,n)=1. If 30(300)+29(301)+⋯+2(3028)+1(3029)=n⋅2m, then n+m is equal to (Here(nk)=nCk)
Answer» Let $m, n \in N$ and $gcd (2, n) = 1.$ If $30 (\begin{matrix} 300 \end{matrix}) + 29 (\begin{matrix} 301 \end{matrix}) + \dots + 2 (\begin{matrix} 3028 \end{matrix}) + 1 (\begin{matrix} 3029 \end{matrix}) = n \cdot 2^{m},$ then $n + m$ is equal to $(Here (\begin{matrix} n k \end{matrix}) =^{n} C_{k})$

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