1.

Let mu, beta, gammaare the roots of the equation x^3 + 2x^2 + 3x + 1 = 0. If the value of (1/beta^(3) + 1/gamma^(3) -1/alpha^(3)) (1/alpha^(3)+1/gamma^(3) -1/beta^(3)) +(1/alpha^(3) + 1/beta^(3) -1/gamma^(3)) (1/alpha^(3) + 1/gamma^(3) -1/beta^(3)) + (1/alpha^(3) + 1/beta^(3) -1/gamma^(3)) (1/beta^(3) + 1/gamma^(3) - 1/alpha^(3)) is lambda. Then find the sum of digit of |lambda|

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ANSWER :172


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