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Let `n=180`. Find the number of positive integral divisors of `n^2`, which do not divide n |
Answer» n=180=20*4 n=`2^2*3^2*5` `D_1=(2+1)(2+1)(1+1)-1` `D_1=17-(1)` `n^2=2^4*3^4*5^2` `D_2=(4+1)(4+1)(3)-2` `D_2=73-(2)` subtracting equation 1 from 2 =73-17=56 is our required number. |
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