Let ω be a complex cube root of unity with ω≠0 and P=[pij] be an n – InterviewSolution

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1.	Let ω be a complex cube root of unity with ω≠0 and P=[pij] be an n×n matrix with Pij=ωi+j. Then P2=0 when n is equal to
Answer» Let $ω$ be a complex cube root of unity with $ω \neq 0$ and $P = [p_{i j}]$ be an $n \times n$ matrix with $P_{i j} = ω^{i + j}$ . Then $P^{2} = 0$ when n is equal to

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