Let ω be a complex cube root of unity with ω≠1 and P=[pij] be a n� – InterviewSolution

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1.	Let ω be a complex cube root of unity with ω≠1 and P=[pij] be a n×n matrix with pij=ωi+j. Then P2≠0, when n=
Answer» Let $ω$ be a complex cube root of unity with $ω \neq 1$ and $P = [p_{i j}]$ be a $n \times n$ matrix with $p_{i j} = ω^{i + j}$ . Then $P^{2} \neq 0$ , when $n =$

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