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Let ω be a complex number such that 2ω+1=z where z=√−3. If ∣∣∣∣∣1111−ω2−1ω21ω2ω7∣∣∣∣∣=3k, then k is equal to: |
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Answer» Let ω be a complex number such that 2ω+1=z where z=√−3. If ∣∣ |
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