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Let omega be the angular velocity of the earth's rotation about its axis. An object weighted by a spring balance gives the same reading at the equator as at a height h above the poles (h lt lt R). The value of h is |
Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) R^(2))/(g)`<br/>`(omega^(2) R^(2))/(2g)`<br/>`(2omega^(2) R^(2))/(g)`<br/>`(sqrt(<a href="https://interviewquestions.tuteehub.com/tag/rg-1188560" style="font-weight:bold;" target="_blank" title="Click to know more about RG">RG</a>))/(omega)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |