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Let omega ne 1 be a cube root of unity. Then the minimumof the set {|a+bomega+c omega^2|^2:a,b,c "distinct non -zero integers"} equals.............

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Solution :Given , `OMEGA ne 1 ` be a CUBE root of unity, then ` |a +b Omega +c Omega ^2|^2`
` =(a+bOmega +cOmega^2)bar((a+bOmega +cOmega^2)),(because zbar(z)=|z|^2)`
`=(a+bOmega +cOmega^2)(a+b bar(Omega)+2c bar(Omega)^2)`
`=a^2+b^2+c^2+ab)(Omega^2+Omega)+b(Omega^2+Omega^4)+ac(Omega +Omega^2)"" ["as" Omega^3=1]`
` =a^2+b^2+c^2+ab)(-1)+bc(-1)+ac(-1)"" [" as" Omega+ Omega^2=-1,Omega^4=Omega]`
`=a^2+b^2+c^2-ab-bc-ca`
`=(1)/(2){(a-b)^2+(b-c)^2+(c-a)^2}`
`because a, b and c` are DISTINCT non - zero integers, For minimum VALUE `a=1,b=2 and c=3`
`THEREFORE |a+b Omega +cOmega^2|_("min")^(2)=(1)/(2){1^2+1^2+2^2}`.
` =(6)/(2) =300`.


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