1.

Let one end of focal chord of parabola y2 = 8x is (1/2, 2), then equation of tangent at other end of this focal chord is (1) x + 2y + 8 = 0 (2) x + 2y = 8(3) x – 2y = 8 (4) x – 2y + 8 = 0

Answer»

Answer is (4)

Let (1/2, - 2) is (2t2, 4t) ⇒ t = -1/2

Parameter of other end of focal chord is 2

⇒  point is (8, 8)

⇒ equation of tangent is 8y – 4(x + 8) = 0

⇒ 2y – x = 8 



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