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Let one end of focal chord of parabola y2 = 8x is (1/2, 2), then equation of tangent at other end of this focal chord is (1) x + 2y + 8 = 0 (2) x + 2y = 8(3) x – 2y = 8 (4) x – 2y + 8 = 0 |
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Answer» Answer is (4) Let (1/2, - 2) is (2t2, 4t) ⇒ t = -1/2 Parameter of other end of focal chord is 2 ⇒ point is (8, 8) ⇒ equation of tangent is 8y – 4(x + 8) = 0 ⇒ 2y – x = 8 |
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