Let p=2520, x=number of divisors of p which are multiple of 6, y=number of divisors of p which are multiple of 9, thenA. x=12B. x=24C. y=12D. y=16

Let p=2520, x=number of divisors of p which are multiple of 6, y=numbe

1.	Let p=2520, x=number of divisors of p which are multiple of 6, y=number of divisors of p which are multiple of 9, thenA. x=12B. x=24C. y=12D. y=16
Answer» Correct Answer - B::D `becausep=2520=2^(3)3^(2)5^(1)7^(1)` `=62^(2)3^(1)5^(1)7^(1)=92^(3)5^(1)7^(1)` `thereforex=(2+1)(1+1)(1+1)(1+1)=24` and `y=(3+1)(1+1)(1+1)=16`.

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Let p=2520, x=number of divisors of p which are multiple of 6, y=number of divisors of p which are multiple of 9, thenA. x=12B. x=24C. y=12D. y=16

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