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Let `P(3,2,6)`be a point in space and `Q`be a point on line ` vec r=( hat i- hat j+2 hat k)+mu(-3 hat i+ hat j+5 hat k)dot`Then the value of `mu`for which the vector ` vec P Q`is parallel to the plane `x-4y+3z=1`isa. 1/4 b. -1/4 c. 1/8 d. -1/8A. `1/4`B. `-1/4`C. `1/8`D. `-1/8` |
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Answer» Correct Answer - A Let the position vector of `Q` be `(hati-hatj+2hatk)+mu(-3hati+hatj+5hatk)` `=(-3mu+1)hati+(mu-1)hatj+(5mu2)hatk`. Then `vec(PQ)=(-3mu-2)hati+(mu-3)hatj+(5mu-4)hatk` It is given that `vec(PQ)` is parallel to the plane `x-4y+3z=1` whose normal is `vecn=hati-4hatj+3hatk`. `:.vec(PQ).vecn(n)=0` `implies(-3mu-2)=4(mu-3)+3(5mu-4)=0impliesmu=1/4` |
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