Let P be a plane passing through the points (1,0,1),(1,−2,1) and (0,1,−2). Let a vector →a=α^i+β^j+γ^k be such that →a is parallel to the plane P, perpendicular to (^i+2^j+3^k) and →a⋅(^i+^j+2^k)=2. Then (α−β+γ)2 equals

Let P be a plane passing through the points (1,0,1),(1,−2,1) and (0,

1.	Let P be a plane passing through the points (1,0,1),(1,−2,1) and (0,1,−2). Let a vector →a=α^i+β^j+γ^k be such that →a is parallel to the plane P, perpendicular to (^i+2^j+3^k) and →a⋅(^i+^j+2^k)=2. Then (α−β+γ)2 equals
Answer» Let $P$ be a plane passing through the points $(1, 0, 1), (1, - 2, 1)$ and $(0, 1, - 2) .$ Let a vector $\to a = α^i + β^j + γ^k$ be such that $\to a$ is parallel to the plane $P$ , perpendicular to $(^i + 2^j + 3^k)$ and $\to a \cdot (^i +^j + 2^k) = 2.$ Then $(α - β + γ)^{2}$ equals