1.

Let P, Q, R and S be the points on the plane with position vectors -2hati-hatj, 4hati, 3hati+3hatj and -3hati+2hatj respectively. The quadrilateral PQRS must be a

Answer»

parallelogram, which is NEITHER a rhombus nor a ractangle
square
rectangle, but not a square
rhombus, but not a square

Solution :Now , `PQ=6hat(i)+hat(J)`
`QR=-hat(i)+3hat(j)`
`RS=-6hat(i)-hat(j)`
`SP=hat(i)-3hat(j)`
`rArr |PQ|=sqrt(37)=|RS|`
`|QR|=sqrt(10)=|SP|`
`therefore PQ.QR=-6+3=-3 NE 0` .


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