Let P1:x+y+z+1=0,P2:x−y+2z+1=0,P3:3x+y+4z+7=0 be three planes, then – InterviewSolution

1.	Let P1:x+y+z+1=0,P2:x−y+2z+1=0,P3:3x+y+4z+7=0 be three planes, then the distance of the line of intersection of the planes P1=0 and P2=0 from the plane P3=0 is
Answer» Let $P_{1} : x + y + z + 1 = 0, P_{2} : x - y + 2 z + 1 = 0, P_{3} : 3 x + y + 4 z + 7 = 0$ be three planes, then the distance of the line of intersection of the planes $P_{1} = 0$ and $P_{2} = 0$ from the plane $P_{3} = 0$ is

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