Saved Bookmarks
| 1. |
Let parabolas `y=x(c-x)` and `y=x^(2)+ax+b` touch each other at the point `(1,0)` then `b-c=` |
|
Answer» Correct Answer - 1 `y=x(c-x) y=x^(2)+ax+b` `(dy)/(dx):|_("(1,0)")` `=c-2m_(1)(dy)/(dx):|_("(1,0)")=2x+a=2+a=m_(2)` Curve are touching at `(1,0)` so `m_(1)=m_(2)` `2+a=c-2`………..i Also `(1,0)` lies both the curve so `c=1`……….ii and `a+b=-1`……….iii by i, ii, iii `b=2,c=1,a=-3` |
|