Let Pk be a point on the curve y=lnx in xy−plane whose x coordinate – InterviewSolution

1.	Let Pk be a point on the curve y=lnx in xy−plane whose x coordinate is 1+kn, k=1,2,3,…,n. If A is (1,0), then limn→∞1nn∑k=1(APk)2 equals (Here, APk is the distance between points A and Pk)
Answer» Let $P_{k}$ be a point on the curve $y = ln x$ in $x y -$ plane whose $x$ coordinate is $1 + \frac{k}{n},$ $k = 1, 2, 3, \dots, n .$ If $A$ is $(1, 0),$ then $lim n \to \infty \frac{1}{n} n \sum k = 1 {(A P_{k})}_{k}^{2}$ equals (Here, $A P_{k}$ is the distance between points $A$ and $P_{k}$ )

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