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Let Pk be a point on the curve y=sin2x, whose x coordinate is kn−1 (k=1,2,3,...,n). If A is (−1,0), then limn→∞1nn∑k=1(APk)2=A−Bsin2, then the value of 3AB is |
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Answer» Let Pk be a point on the curve y=sin2x, whose x coordinate is kn−1 (k=1,2,3,...,n). If A is (−1,0), then limn→∞1nn∑k=1(APk)2=A−Bsin2, then the value of 3AB is |
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