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Let Q0 be the set of all nonzero rational numbers. Let * be a binary operation on Q0, defined by a * b = ab/4 for all a, b ∈ Q0.(i) Show that * is commutative and associative.(ii) Find the identity element in Qo.(iii) Find the inverse of an element a in Q0. |
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Answer» It is given that a * b = ab/4 (i) For a, b, c ∈ Q0 We know that a * b = ab/4 = ba/4 = b * a (a * b) * c = ab/ 4 * c = [ab/4 * c]/ 4 = (ab) c/ 16 a * (b * c) = a * bc/4 = [a(bc/4)]/ 4 = a (bc)/16 Here, (ab) c = a (bc) Therefore, (a * b) * c = a * (b * c) (ii) Consider e as the identity element and a ∈ Q0 Here, a * e = a So we get ae/4 = a where e = 4 Hence, 4 is the identity element in Q. (iii) Consider a ∈ Q0 which is inverse b a * b = e So we get ab/4 = 4 Here, b = 16/a ∈ Q0 Hence, a ∈ Q0 has 16/a as inverse. |
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