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Let `R_(1)= {(x,y)in RxxR :x = lambda y implies lambda in Q}` is a relation, R is set of real numbers then `R_(1)` isA. equivalenceB. only symmetricC. not symmetricD. not reflexive |
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Answer» Correct Answer - C Let `R_(1) = {(x,y)in RxxR : x = lambda y}` ………. `x = lambda x implies lambda = 1 epsilon Q` reflexive `(x)/(y)= lambda` is rotional `implies (y)/(x) = (1)/(lambdas)` may or may not be rational for example `lambda = 0` `epsilon Q` But `(1)/(lambda) = (1)/(0)cancelepsilon Q` so not symmetric |
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