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Let R be a relation in the set of integer I defined by aRb iff a & b both are neither even nor odd. Then show that R is symmetric but neither reflexive nor transitive. |
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Answer» Given relation aRb is defined only when, both a & b are not even or odd at a time. i.e., if a is even & b is odd then aRb is well defined. (i) Let a and be odd and even then aRb is defined and aRb ⇒ bRa Hence, R is symmetric. (ii) Let a be an odd then aRa is not defined and a be an even then also aRa is not defined. So, R is not reflexive. (iii) Let a and b be odd and even respectively. Then if R is transitive, then aRb, bRa ⇒ aRa but, then aRa is not defined as a is odd. Hence, R is not transitive. |
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