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Let `R` be the relation defined on power set of A such that `ARB hArr n(P(A)) = n(P(B))` can be : (where `P(A)` denotes power set of `(A)`A. ReflexiveB. SymmetricC. TransitiveD. Equiivalence |
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Answer» Correct Answer - A::B::C::D Let `R` be the ……….. `(A.B) in R implies n(P(A)) = n(P(B))` `implies 2^(n(A)) = 2^(n(B))` Now, `n(A)=n(A) implies (A,A)in R AA A` `implies R` is reflexive Let `(A,B) in R implies n(A) = n(B) implies n(B)= n(A) implies (B,A) in R` `:.` symmetric Let `(A,B) in R implies n(A)=n(B)` Let `(B,C)in R implies n(B) = n(C )` `implies n(A) = n(C )` `implies (A,C)in R :.` transitive `:.` equivalence |
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