Let S=1sin 8∘+1sin 16∘+1sin 32∘+……+1sin 4096∘+1sin 8192∘ – InterviewSolution

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1.	Let S=1sin 8∘+1sin 16∘+1sin 32∘+……+1sin 4096∘+1sin 8192∘. If S=1sin α, where α∈(0,90∘), then α (in degree) is
Answer» Let $S = \frac{1}{sin 8^{\circ}} + \frac{1}{sin 16^{\circ}} + \frac{1}{sin 32^{\circ}} + \dots \dots + \frac{1}{sin 4096^{\circ}} + \frac{1}{sin 8192^{\circ}}$ . If $S = \frac{1}{sin α}$ , where $α \in (0, 90^{\circ})$ , then $α$ (in degree) is

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