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Let S=2x1−x2+2y1−y2+2z1−z2 and T=8xyz(1−x2)(1−y2)(1−z2), where x,y,z≠±1. If x+y+z=xyz, then the value of S−T is

Answer»

Let S=2x1x2+2y1y2+2z1z2 and
T=8xyz(1x2)(1y2)(1z2), where x,y,z±1. If x+y+z=xyz, then the value of ST is



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