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Let S1 be the sum of first 2n terms of an arithemetic progression. Let S2 be the sum of first 4n terms of the same arithmetic progression. If (S2−S1) is 1000 then sum of the first 6n terms of the arithmetic progression is equal to : |
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Answer» Let S1 be the sum of first 2n terms of an arithemetic progression. Let S2 be the sum of first 4n terms of the same arithmetic progression. If (S2−S1) is 1000 then sum of the first 6n terms of the arithmetic progression is equal to : |
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