Let S1 be the sum of first 2n terms of an arithemetic progression. Let – InterviewSolution

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1.	Let S1 be the sum of first 2n terms of an arithemetic progression. Let S2 be the sum of first 4n terms of the same arithmetic progression. If (S2−S1) is 1000 then sum of the first 6n terms of the arithmetic progression is equal to :
Answer» Let $S_{1}$ be the sum of first $2 n$ terms of an arithemetic progression. Let $S_{2}$ be the sum of first $4 n$ terms of the same arithmetic progression. If $(S_{2} - S_{1})$ is $1000$ then sum of the first $6 n$ terms of the arithmetic progression is equal to :

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