Let Sigma_(n)^(n-1) vec(a_(i))=0 , where |vec(a_(i))|=1AAi, then Sigma_(1leiltjlen)Sigmavec(a_(i))vec(a_(j))=

Let Sigma_(n)^(n-1) vec(a_(i))=0 , where |vec(a_(i))|=1AAi, then Sigma

1.	Let Sigma_(n)^(n-1) vec(a_(i))=0 , where \|vec(a_(i))\|=1AAi, then Sigma_(1leiltjlen)Sigmavec(a_(i))vec(a_(j))=
Answer» N `-n` `(n)/(2)` `(-n)/(2)` Solution :Given expression `[(vec(a)xxvec(B))XX(vec(b)xxvec(C))(vec(b)xxvec(c))xx(vec(c)xxvec(a))(vec(c)xxvec(a))xx(vec(a)xxvec(b))]=[[vec(a)vec(b)vec(c)]vec(b)[ ]vec(c)[ ]vec(a)]=[vec(a)vec(b)vec(c)]^(4)`

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Let Sigma_(n)^(n-1) vec(a_(i))=0 , where |vec(a_(i))|=1AAi, then Sigma_(1leiltjlen)Sigmavec(a_(i))vec(a_(j))=

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