1.

Let T_(1) and T_(2) be the time periods of two springs A and B when a mass m is suspended from them separately. Now both the springs are connected in parallel and same mass m is suspended with them. Now let T be the time period in this position. Then

Answer»

`T = T_(1)+T_(2)`
`T=(T_(1)T_(2))/(T_(1)+T_(2))`
`T^(2)= T_(1)^(2)+T_(2)^(2)`
`1/T^(2)=1/T_(1)^(2)+1/T(2)^(2)`

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