Let the colour of the indicator (Hin colourles) will be visible only when its ionised form (pink) is 25 or more in a solution. Suppose Hln (pK_(In) = 9.0) is added to a solution of pH = 9.6. Predict what will happen. (Take log 2 = 0.3)

Let the colour of the indicator (Hin colourles) will be visible only w

1.	Let the colour of the indicator (Hin colourles) will be visible only when its ionised form (pink) is 25 or more in a solution. Suppose Hln (pK_(In) = 9.0) is added to a solution of pH = 9.6. Predict what will happen. (Take log 2 = 0.3)
Answer» Pink colour will be visible Pink colour will not be visible % of ionised form will be less than 25% % of ionised form will be more than 25% Solution :` pH =PKA +LOG "" ([In^(-) ])/( [HIn]) , ` ` 9. 6 = 9+ log ""([In^(-) ])/( [HIn ]), 0. 6 = log ""([ In^(-)])/( [HIn ]), ([In^(-) ])/( [H In ]) = 4 ` ` rArr([In^(-) ])/([In ^(-)]+[HIn ])XX 100 = (4)/(3)xx 100 = 80%`