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Let the equation of the plane containing line x−y−z−4=0=x+y+2z−4 and parallel to the line of intersection of the planes 2x+3y+z=1 and x+3y+2z=2 be x+Ay+Bz+C=0. Then the value of |A+B+C−4| is |
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Answer» Let the equation of the plane containing line x−y−z−4=0=x+y+2z−4 and parallel to the line of intersection of the planes 2x+3y+z=1 and x+3y+2z=2 be x+Ay+Bz+C=0. Then the value of |A+B+C−4| is |
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