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Let the sides of a triangle ABC are all integers with A as the origin. If (2, -1) and (3, 6) are points on the line AB and AC, respectively, (lines AB and AC may be extended to contain these points), and lengths of any two sides are primes that differ by 50. If a is least possible length of the third side and S is the least possible perimeter of the triangle then aS is equal to K^(2) where K =

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ANSWER :`88.99`


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