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Let Tn=(n2+1)n! and Sn=T1+T2+T3+⋯+Tn. If T10S10=ab, where a and b are relatively prime natural numbers, then the value of (b−a) is

Answer»

Let Tn=(n2+1)n! and Sn=T1+T2+T3++Tn. If T10S10=ab, where a and b are relatively prime natural numbers, then the value of (ba) is



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