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Let two independent eventsA and Bsuch that P(A)=0.3,P(B)=0.6 FindP(A and not B) |
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Answer» <P> SOLUTION :GIVEN that P (A) = 0.3 and P(B) = 0.6therefore `P(A^c)`= 1-P(A) = 1-0.3=0.7`P(B^c)` = 1-P(B) = 1-0.6=0.4 =`P(A)P(B^c)` `0.3xx0.4`=0.12 |
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