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Let two independent eventsA and Bsuch that P(A)=0.3,P(B)=0.6 FindP(A or B)

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SOLUTION :GIVEN that P (A) = 0.3 and P(B) = 0.6therefore `P(A^c)`= 1-P(A) = 1-0.3=0.7
`P(B^c)` = 1-P(B) = 1-0.6=0.4
ANNB)`
=P(A)+P(B)-`P(AnnB)`
+0.3+0.6-0.18
+0.9-0.18=0.72


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