1.

Let us say that X is a normally distributed variable with mean(μ) of 43 and standard deviation (σ) of 6.4. Determine the probability of X

Answer»

Right choice is (a) 0.341

To elaborate: The area is defined as the area under the standard normal curve.Now, for X = 32, z becomes \(\FRAC{32 – 43}{6.4}\) = -1.71. Hence, the required PROBABILITY is P(x < 32) = P(z < -1.71) = 0.341.



Discussion

No Comment Found

Related InterviewSolutions