1.

Let V denote the root mean square speed of the molecules in an ideal diatomic gas at absolute temperature T. The mass of a molecule is m. Neglecting vibrational energy terms, which is True?

Answer»

a MOLECULE can have a speed greater than `sqrt(2)v`
v is proportional to `sqrt(T) `
the average ROTATIONAL kinetic energy of a molecule is `(mv^(2))/(4)`
the average kinetic energy of a molecule is `(5mv^(2))/(6)`

Solution :AVG.`K.E.=(5)/(2)KT=(5)/(6)mv^(2)""[:.(1)/(2)mv^(2)=(3)/(2)KT]`


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