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Let `vec(A)=hat(i)A cos theta+hat(j)A sin theta`, be any vector. Another vector `vec(B)` which is normal to `vec(A)` is :-A. `B costheta hati +B sin thetahatj`B. `B sin theta hati +B cos thetahatj`C. `B sin theta hati - B cos thetahatj`D. `A cos theta hati - A cos thetahatj` |
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Answer» Correct Answer - C `vec(A)= A cos theta hati +A sin theta J` We must have `vecA.vecB=0,` which is cleaely satisfied by `vec(B) =B sin theta hati -A cos theta hatj.` |
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